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If
$x-1 \quad$ is
$x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$, then $k$ is
$a$
Options:
$x-1 \quad$ is
$x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$, then $k$ is
$a$
Solution:
2239 Upvotes
Verified Answer
The correct answer is:
4
Since, $x-1$ is a factor of $x^{5}-4 x^{3}+2 x^{2}-3 x+k=0$
Therefore, $x=1$ must satisfy the given equation.
$\therefore \quad(1)^{5}-4(1)^{3}+2(1)^{2}-3(1)+\mathrm{k}=0$
$1-4+2-3+k=0$
$\Rightarrow \quad \mathrm{k}=4$
Therefore, $x=1$ must satisfy the given equation.
$\therefore \quad(1)^{5}-4(1)^{3}+2(1)^{2}-3(1)+\mathrm{k}=0$
$1-4+2-3+k=0$
$\Rightarrow \quad \mathrm{k}=4$
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