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Question: Answered & Verified by Expert
If x1, x2, .., xn and 1h1, 1h2, .., 1hn are two A.P.s such that x3=h2=8 & x8=h7=20, then x5·h10 is equal to
MathematicsSequences and SeriesJEE MainJEE Main 2018 (15 Apr)
Options:
  • A 3200
  • B 1600
  • C 2650
  • D 2560
Solution:
2809 Upvotes Verified Answer
The correct answer is: 2560

Let d1 be the common difference of the A.P. x1,x2,, then x8-x3=5 d1=12

x5=x3+2 d1=8+2×125=12.8

Let d2 be the common difference of the other sequence then

5 d2=120-18=-340d2

1 h10=1 h7+3 d2=1200h10=200

x5·h10=12.8×200=2560

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