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If $x_1, x_3$ are the roots of $A x^2-4 x+1=0$ and $x_2, x_4$ are the roots of $B x^2-6 x+1=0$ such that $x_1, x_2, x_3, x_4$ are in harmonic progression, then $\frac{B+A}{B-A}=$
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The correct answer is:
$\frac{11}{5}$
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