If x 2 - 5 x - 14 0 ⇒ x lie outside [ α , β ] , then α β =

Question

If x 2 - 5 x - 14 > 0 ⇒ x lie outside [ α , β ] , then α β =, - 2 7, - 7 2, 2 7, 7 2

MARKS App · Accepted Answer

x 2 - 5 x - 14 > 0 ⇒ x + 2 x - 7 > 0 ⇒ x ∈ - ∞ , - 2 ∪ 7 , ∞ As per question, the interval for which x lies outside is α , β ⇒ α = - 2 , β = 7 So, α β = - 2 7

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