Search any question & find its solution
Question:
Answered & Verified by Expert
If $x^3+8 x y+y^3=64$, then $\frac{d y}{d x}=$
Options:
Solution:
1365 Upvotes
Verified Answer
The correct answer is:
$-\frac{3 x^2+8 y}{8 x+3 y^2}$
$\begin{aligned} & x^3+8 x y+y^3=64 \Rightarrow 3 x^2+8\left(y+x \frac{d y}{d x}\right)+3 y^2 \frac{d y}{d x}=0 \\ & \therefore \frac{d y}{d x}=-\frac{3 x^2+8 y}{8 x+3 y^2} .\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.