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Question: Answered & Verified by Expert
If $x^3+8 x y+y^3=64$, then $\frac{d y}{d x}=$
MathematicsDifferentiationJEE Main
Options:
  • A $-\frac{3 x^2+8 y}{8 x+3 y^2}$
  • B $\frac{3 x^2+8 y}{8 x+3 y^2}$
  • C $\frac{3 x+8 y^2}{8 x^2+3 y}$
  • D None of these
Solution:
1365 Upvotes Verified Answer
The correct answer is: $-\frac{3 x^2+8 y}{8 x+3 y^2}$
$\begin{aligned} & x^3+8 x y+y^3=64 \Rightarrow 3 x^2+8\left(y+x \frac{d y}{d x}\right)+3 y^2 \frac{d y}{d x}=0 \\ & \therefore \frac{d y}{d x}=-\frac{3 x^2+8 y}{8 x+3 y^2} .\end{aligned}$

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