If x = 3 is the chord of contact of the circle x 2 + y 2 = 81 , then the equation of the corresponding pair of tangents, is

Question

If x = 3 is the chord of contact of the circle x 2 + y 2 = 81 , then the equation of the corresponding pair of tangents, is, x 2 - 8 y 2 + 5 4 x + 7 2 9 = 0, x 2 - 8 y 2 - 5 4 x + 7 2 9 = 0, x 2 - 8 y 2 - 5 4 x - 7 2 9 = 0, x 2 - 8 y 2 = 7 2 9

MARKS App · Accepted Answer

Put x = 3 in the equation of circle to get the point of contact, y = ± 6 2 Hence, equation of the pair of tangents is 3 x + 6 2 y - 8 1 3 x - 6 2 y - 8 1 = 0 x - 2 7 2 - 8 y 2 = 0 x 2 - 5 4 x - 8 y 2 + 7 2 9 = 0

Search any question & find its solution

Looking for more such questions to practice?