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 If $x=a t+b t^{2},$ where $x$ is in metre $(\mathrm{m})$ and $t$ is in hour $(\mathrm{h})$, then unit of $b$ will be
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The correct answer is:
$\frac{m}{h^{2}}$ 
 Given, $x=a t+b t^{2}$
$\begin{array}{l}
{[x]=\left[b t^{2}\right]} \\
\text { Unit of } b=\frac{x}{t^{2}}=\frac{\text { metre }}{(h)^{2}}=\frac{m}{h^{2}}
\end{array}$
 $\begin{array}{l}
{[x]=\left[b t^{2}\right]} \\
\text { Unit of } b=\frac{x}{t^{2}}=\frac{\text { metre }}{(h)^{2}}=\frac{m}{h^{2}}
\end{array}$
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