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If $x$ and $y$ are connected parametrically by the given equations, without eliminating the parameter. Find $\frac{d y}{d x}$
$x=4 t, y=\frac{4}{t}$
$x=4 t, y=\frac{4}{t}$
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$\frac{d x}{d t}=4 ; \quad \frac{d y}{d t}=\frac{-4}{t^2} \Rightarrow \frac{d y}{d x}=\frac{-4}{t^2} \times \frac{1}{4}=\frac{-1}{t^2}$
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