Search any question & find its solution
Question:
Answered & Verified by Expert
If $x$ gram of gas is adsorbed by $m$ gram of adsorbent at pressure $P$ the plot of $\log \frac{x}{\mathrm{~m}}$ versus $\log \mathrm{P}$ is linear. The slope of the plot is: ( $\mathrm{m}$ and $\mathrm{k}$ are constants and $n>1$ )
Options:
Solution:
2282 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{n}$
$\frac{1}{n}$
According to Freundlich adsorption isotherm.
$$
\begin{aligned}
&\frac{\mathrm{x}}{\mathrm{m}}=\mathrm{kP}^{\frac{1}{\mathrm{n}}} \\
&\log _{10} \frac{\mathrm{x}}{\mathrm{m}}=\frac{1}{\mathrm{n}} \log _{10} \mathrm{P}+\log _{10} \mathrm{k}
\end{aligned}
$$
This is the equation of straight line of type $y=m x+c$
Hence slope is $1 / \mathrm{n}(\mathrm{m})$ and intercept is $\log _{\mathrm{e}} \mathrm{k}$.
$$
\begin{aligned}
&\frac{\mathrm{x}}{\mathrm{m}}=\mathrm{kP}^{\frac{1}{\mathrm{n}}} \\
&\log _{10} \frac{\mathrm{x}}{\mathrm{m}}=\frac{1}{\mathrm{n}} \log _{10} \mathrm{P}+\log _{10} \mathrm{k}
\end{aligned}
$$
This is the equation of straight line of type $y=m x+c$
Hence slope is $1 / \mathrm{n}(\mathrm{m})$ and intercept is $\log _{\mathrm{e}} \mathrm{k}$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.