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If $X$ is a r. v. with c. d. f. $F(x)$ and its probability distribution is given by

then, $\mathrm{F}(1 \cdot 5)-\mathrm{F}(-0 \cdot 5)=$
Options:

then, $\mathrm{F}(1 \cdot 5)-\mathrm{F}(-0 \cdot 5)=$
Solution:
1345 Upvotes
Verified Answer
The correct answer is:
$0 \cdot 4$
(B)
$\begin{array}{l}
F(1.5)-F(-0.5) \\
=P[X \leq 1.5]-P[X \leq-0.5] \\
=[P(X=-1.5)+P(X=-0.5)+P(X=0.5)+P(X=1.5)]-[P(X=-1.5)+P(X=-0.5)] \\
=P(X=0.5)+P(X=1.5)=0.15+0.25=0.4
\end{array}$
$\begin{array}{l}
F(1.5)-F(-0.5) \\
=P[X \leq 1.5]-P[X \leq-0.5] \\
=[P(X=-1.5)+P(X=-0.5)+P(X=0.5)+P(X=1.5)]-[P(X=-1.5)+P(X=-0.5)] \\
=P(X=0.5)+P(X=1.5)=0.15+0.25=0.4
\end{array}$
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