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If $x^n-1$ is divisible by $x-k$, then the least positive integral value of $k$ is
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1
1
Suppose $P(n)=x^n-1$ is divisible by $(x-k)$. For $n=1, P(1)=x^1-1$ is divisible by $(x-k)$. So, the least possible integral value of $k$ is 1 .
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