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Question: Answered & Verified by Expert
If x=sinθ,y=sin3θ then d2ydx2 at θ = π2 is ….
MathematicsDifferentiationMHT CETMHT CET 2019 (Shift 2)
Options:
  • A 3
  • B 6
  • C 16
  • D 13
Solution:
2783 Upvotes Verified Answer
The correct answer is: 6
We have , x=sinθ,y=sin3θ
dydx=dydθdxdθ=3sin2θcosθcosθ
dydx=3sin2θ
Now, d2ydx2=32sinθcosθdθdx
=32sinθcosθ1cosθ=6sinθ
at θ=π2,d2ydx2=6sinπ2=6×1=6

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