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If $\int x \sin x d x=-x \cos x+A$, then $A=$
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Verified Answer
The correct answer is:
$\sin x+$ constant
Since, $\int x \sin x d x=-x \cos x+A$$
\Rightarrow-x \cos x+\sin x+\text { constant }=-x \cos x+A$
Equating it, we get $A=\sin x+$ constant.
\Rightarrow-x \cos x+\sin x+\text { constant }=-x \cos x+A$
Equating it, we get $A=\sin x+$ constant.
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