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If $x, v$ and a denote the displacement, the velocity and the acceleration of a particle executing simple harmonic motion of time period $\mathrm{T}$, then, which of the following does not change with time?
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Verified Answer
The correct answer is:
$\frac{a T}{x}$
$\frac{a T}{x}$
$$
\frac{\text { aT }}{\mathrm{X}}=\frac{\omega^2 \mathrm{XT}}{\mathrm{X}}=\frac{4 \pi^2}{\mathrm{~T}^2} \times \mathrm{T}=\frac{4 \pi^2}{\mathrm{~T}}=\text { constant. }
$$
\frac{\text { aT }}{\mathrm{X}}=\frac{\omega^2 \mathrm{XT}}{\mathrm{X}}=\frac{4 \pi^2}{\mathrm{~T}^2} \times \mathrm{T}=\frac{4 \pi^2}{\mathrm{~T}}=\text { constant. }
$$
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