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If \(x+\frac{1}{x}=2 \cos \theta\), then for any integer \(n, x^n+\frac{1}{x^n}=\)
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Verified Answer
The correct answer is:
\(2 \cos n \theta\)
Hints: \(x+\frac{1}{x}=2 \cos \theta\)
Let \(x=\cos \theta+1 \sin \theta\)
\(\frac{1}{x}=\cos \theta-1 \sin \theta\)
Thus \(x^n+\frac{1}{x^n}=2 \cos n \theta\)
Let \(x=\cos \theta+1 \sin \theta\)
\(\frac{1}{x}=\cos \theta-1 \sin \theta\)
Thus \(x^n+\frac{1}{x^n}=2 \cos n \theta\)
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