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If \( x+y \leq 2, x \geq 0, y \geq 0 \) the point at which maximum value of \( 3 x+2 y \) attained will be
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Verified Answer
The correct answer is:
\( (2,0) \)
Given that $x+y \leq 2 \rightarrow(1)$
$x \geq 0 . y \geq 0 \rightarrow(2)$
Corner points are $(0,0),(2,0),(0,2)$
Maximum of $3 x+2 y$ is at $(2,0)$
$$
\begin{array}{l}
\text { Given that } x+y \leq 2 \rightarrow(1) \\
x \geq 0 . y \geq 0 \rightarrow(2) \\
\text { Corner points are }(0,0),(2,0),(0,2) \\
\text { Maximum of } 3 x+2 y \text { is at }(2,0)
\end{array}
$$
$x \geq 0 . y \geq 0 \rightarrow(2)$
Corner points are $(0,0),(2,0),(0,2)$
Maximum of $3 x+2 y$ is at $(2,0)$
$$
\begin{array}{l}
\text { Given that } x+y \leq 2 \rightarrow(1) \\
x \geq 0 . y \geq 0 \rightarrow(2) \\
\text { Corner points are }(0,0),(2,0),(0,2) \\
\text { Maximum of } 3 x+2 y \text { is at }(2,0)
\end{array}
$$
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