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If $y=1+x+\frac{x^{2}}{2 !}+\frac{x^{3}}{3 !}+\ldots . \infty,$ then $\frac{d y}{d x}$ is equal to
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The correct answer is:
$y$
$y=e^{x} \Rightarrow \frac{d y}{d x}=e^{x}=y$
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