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Question: Answered & Verified by Expert
If y=1+xy+sin-1sin2x, then dydx at x=0 is
MathematicsDifferentiationJEE Main
Options:
  • A 0
  • B ln2
  • C 1
  • D 12
Solution:
1646 Upvotes Verified Answer
The correct answer is: 1

dydx=1+xyy1+x+ln1+xdydx+sin2x1-sin4x
Putting x=0 & y=1, we get,

dydx=11+ln1.dydx+0=1

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