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If $y=2^{\log x}$, then $\frac{d y}{d x}$ is
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1313 Upvotes
Verified Answer
The correct answer is:
$\frac{2^{\log x} \log 2}{x}$
We have,
$$
\begin{gathered}
y=2^{\log x} \\
\therefore \quad \frac{d y}{d x}=2^{\log x} \cdot \log 2 \cdot \frac{d}{d x}(\log x)=\frac{2^{\log x} \log 2}{x}
\end{gathered}
$$
$$
\begin{gathered}
y=2^{\log x} \\
\therefore \quad \frac{d y}{d x}=2^{\log x} \cdot \log 2 \cdot \frac{d}{d x}(\log x)=\frac{2^{\log x} \log 2}{x}
\end{gathered}
$$
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