If y = 2 tan − 1 x + sin − 1 ( 1 + x 2 2 x ) for all x , then y

Question: Answered & Verified by Expert

If $y=2 \tan ^{-1} x+\sin ^{-1}\left(\frac{2 x}{1+x^2}\right)$ for all $x$, then $ < \mathrm{y} < $

MathematicsInverse Trigonometric Functions

Solution:

1958 Upvotes Verified Answer

$-2 \pi, 2 \pi \quad$

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