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If $y^{\prime \prime}-3 y^{\prime}+2 y=0$ where $y(0)=1, y^{\prime}(0)=0$, then the value of $y$ at $x=\log , 2$ is
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$$
\begin{aligned}
& \text { Hints: } \frac{d^2 y}{d x^2}-3 \frac{d y}{d x}+2 y=0 \\
& m^2-3 m+2=0, \quad y=A e^x+B e^{2 x} \\
& m=1, m=2, y^1=A e^x+2 B e^{2 x} \\
& y=0, A+B=1 \quad A+2 B=0, A=2, B=-1 \\
& y=2 e^x-e^{2 x} \\
& y=0 \quad \text { at } x=\ell n 2
\end{aligned}
$$
\begin{aligned}
& \text { Hints: } \frac{d^2 y}{d x^2}-3 \frac{d y}{d x}+2 y=0 \\
& m^2-3 m+2=0, \quad y=A e^x+B e^{2 x} \\
& m=1, m=2, y^1=A e^x+2 B e^{2 x} \\
& y=0, A+B=1 \quad A+2 B=0, A=2, B=-1 \\
& y=2 e^x-e^{2 x} \\
& y=0 \quad \text { at } x=\ell n 2
\end{aligned}
$$
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