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Question: Answered & Verified by Expert
If $y=4 x-5$ is tangent to the curve $y^2=p x^3+q$ at $(2,3)$, then
MathematicsApplication of DerivativesMHT CETMHT CET 2022 (07 Aug Shift 1)
Options:
  • A $p=2, q=-7$
  • B $p=2, q=7$
  • C $p=-2, q=7$
  • D $p=-2, q=-7$
Solution:
1351 Upvotes Verified Answer
The correct answer is: $p=2, q=-7$
$\begin{aligned} & (2,3) \text { lies on } y^2=p x^3+q \\ & \Rightarrow 3^2=P \times 2^3+q\end{aligned}$

from (i) and (ii) $q=-7$

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