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If $y=4 x-5$ is tangent to the curve $y^2=p x^3+q$ at $(2,3)$, then
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Verified Answer
The correct answer is:
$p=2, q=-7$
$\begin{aligned} & (2,3) \text { lies on } y^2=p x^3+q \\ & \Rightarrow 3^2=P \times 2^3+q\end{aligned}$

from (i) and (ii) $q=-7$

from (i) and (ii) $q=-7$
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