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If $y=a e^x+b e^{-x}+c$, where $a, b, c$ are parameters, then $y^{\prime \prime \prime}$ is equal to
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Verified Answer
The correct answer is:
$y^{\prime}$
We have,
$$
\begin{aligned}
y & =a e^x+b e^{-x}+c \\
y^{\prime} & =a e^x-b e^{-x} \\
y^{\prime \prime} & =a e^x+b e^{-x} \\
y^{\prime \prime \prime} & =a e^x-b e^{-x}=y^{\prime}
\end{aligned}
$$
$$
\begin{aligned}
y & =a e^x+b e^{-x}+c \\
y^{\prime} & =a e^x-b e^{-x} \\
y^{\prime \prime} & =a e^x+b e^{-x} \\
y^{\prime \prime \prime} & =a e^x-b e^{-x}=y^{\prime}
\end{aligned}
$$
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