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If $y=\sin (\sqrt{\sin x+\cos x})$, then $\frac{d y}{d x}=$
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Verified Answer
The correct answer is:
$\frac{1}{2} \frac{\cos \sqrt{\sin x+\cos x}}{\sqrt{\sin x+\cos x}} \cdot(\cos x-\sin x)$
$\begin{aligned} & y=\sin (\sqrt{\sin x+\cos x}) \\ & \frac{d y}{d x}=\frac{1}{2} \frac{\cos (\sqrt{\sin x+\cos x})}{\sqrt{\sin x+\cos x}}(\cos x-\sin x)\end{aligned}$
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