If y = t a n - 1 x 1 + 6 x 2 + t a n - 1 2 x - 1 2 x + 1 ∀ x 0 , then d y d x is equal to

Question

If y = t a n - 1 x 1 + 6 x 2 + t a n - 1 2 x - 1 2 x + 1 ∀ x > 0 , then d y d x is equal to, 3 1 + 9 x 2, 1 1 + 6 x 2, 1 1 + 6 x 2 + 1 1 + x 2, 3 1 + 6 x 2

MARKS App · Accepted Answer

y = t a n - 1 3 x - 2 x 1 + 3 x ⋅ 2 x + t a n - 1 2 x - 1 1 + 2 x ⋅ 1 y = t a n - 1 3 x - t a n - 1 2 x + t a n - 1 2 x - tan - 1 1 y = t a n - 1 3 x - π 4 ⇒ d y d x = 3 1 + 9 x 2

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