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Question: Answered & Verified by Expert
If y=tan-1ax-bbx+a, then y'=
MathematicsDifferentiationAP EAMCETAP EAMCET 2021 (20 Aug Shift 1)
Options:
  • A 11+x2+a2a2+b2
  • B 11+x2
  • C 11+ax-bbx+a2
  • D bx+a1+(ax-b)2
Solution:
1755 Upvotes Verified Answer
The correct answer is: 11+x2

y=tan-1ax-bbx+a

dydx=11+ax-bbx+a2×bx+aa-ax-bbbx+a2

dydx=11+ax-bbx+a2×a2+b2bx+a2

dydx=a2+b2b2x2+a2+2abx+a2x2+b2-2abx=a2+b2x2a2+b2+a2+b2

dydx=1x2+1

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