If y = tan - 1 ⁡ x 2 then x 2 + 1 2 d 2 y d x 2 + 2 x x 2 + 1 d y d x =

Question

If y = tan - 1 ⁡ x 2 then x 2 + 1 2 d 2 y d x 2 + 2 x x 2 + 1 d y d x =, 4, 2, 1, 0

MARKS App · Accepted Answer

y = ( tan − 1 x ) 2 d y d x = 2 tan − 1 ( x ) ( 1 + x 2 ) ( 1 + x 2 ) d y d x = 2 tan − 1 ( x ) ( 1 + x 2 ) d 2 y d x 2 + d y d x ( 2 x ) = 2 1 + x 2 ( 1 + x 2 ) 2 d 2 y d x 2 + 2 x ( x 2 + 1 ) d y d x = 2

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