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If $y=\left(x+\sqrt{1+x^2}\right)^n$, then $\left(1+x^2\right) \frac{d^2 y}{d x^2}+x \frac{d y}{d x}$ is
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The correct answer is:
$\mathrm{n}^2 \mathrm{y}$
$\mathrm{n}^2 \mathrm{y}$

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