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Question: Answered & Verified by Expert
If yx is a solution of dydx-xy1 + x=11 + x and y0=-1, then the value of y2 is
MathematicsDifferential EquationsJEE Main
Options:
  • A -12
  • B -13
  • C -14
  • D -15
Solution:
1486 Upvotes Verified Answer
The correct answer is: -13
I.F.=e-x1+xdx=e-x+1-1x+1dx=e-x+lnx+1

= e-x·|(x+1)|

y·x+1ex=x+1x+1e-xdx+c

y·|(x+1)|ex=-| x+1 |x+1e-x+c

 y=-1x+1+cex| x+1 |

x=0, y=-1 -1=-1+c c=0

   y=-11+x

y2=-13

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