If $y=2 x^3-2 x^2+3 x-5$, then for $x=2$ and $\Delta x=0.1$ value of $\Delta y$ is

Question

If $y=2 x^3-2 x^2+3 x-5$, then for $x=2$ and $\Delta x=0.1$ value of $\Delta y$ is, 2.002, 1.9, 0, 09

MARKS App · Accepted Answer

$\text { Hints: } \frac{\mathrm{dy}}{\mathrm{dx}}=6 \mathrm{x}^2-4 \mathrm{x}+3 \quad \Delta \mathrm{y}=\left(\frac{\mathrm{dy}}{\mathrm{dx}}\right)_{\mathrm{x}-2} \Delta \mathrm{x}=1.9$

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