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Question: Answered & Verified by Expert
If z=ax+by;a,b>0 subject to x2,y2,x+y3,x0,y0 has minimum value at 2,1 only, then…
MathematicsArea Under CurvesMHT CETMHT CET 2019 (Shift 1)
Options:
  • A a>b
  • B a=b
  • C a<b
  • D a=1+b
Solution:
1970 Upvotes Verified Answer
The correct answer is: a<b
We have, z=ax+by,a,b>0
Subject to constraints x2,y2,x+y3x,y0
On taking given constraints as equation, we get the following graph

Here, ABCA is the required feasible region whose corner points are A2,1,B1,2 and C2,2 .
Since, It is given that z=ax+by;a,b>0
has minimum value at 2,1
Value of z at 2,1< value of z at 1,2
2a+b<a+2b
a<b

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