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If $|z+i|-|z-1|=|z|-2=0$ for a complex number $z$, then $z=$
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Verified Answer
The correct answers are:
$\sqrt{2}(1-i)$, $\sqrt{2}(-1+i)$
$|z| =2$ represents circle
$|z+i|=|z-1|$ represents
Solving $x^{2}+y^{2}=4$ and $y=-x$
$z=\sqrt{2}(1-i), \quad \sqrt{2}(-1+i)$
$|z+i|=|z-1|$ represents
Solving $x^{2}+y^{2}=4$ and $y=-x$
$z=\sqrt{2}(1-i), \quad \sqrt{2}(-1+i)$
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