If z is a complex number, then the area of the triangle (in sq. units) whose vertices are the roots of the equation z 3 + i z 2 + 2 i = 0 is equal to (where, i 2 = - 1 )

Question

If z is a complex number, then the area of the triangle (in sq. units) whose vertices are the roots of the equation z 3 + i z 2 + 2 i = 0 is equal to (where, i 2 = - 1 ),

MARKS App · Accepted Answer

z - i z 2 + 2 i z - 2 = 0 ⇒ z = i , 1 - i , - 1 + i A r e a = 1 2 0 1 1 1 - 1 1 - 1 - 1 1 = - 2 = 2 sq. units

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