Search any question & find its solution
Question:
Answered & Verified by Expert
If $Z_r=\cos \left(\frac{\pi}{2^r}\right)+i \sin \left(\frac{\pi}{2^r}\right)$ for $r=1,2,3, \ldots$. , then $Z_1 Z_2 Z_3 \ldots \infty$ equals to
Options:
Solution:
1616 Upvotes
Verified Answer
The correct answer is:
$-1$
$\begin{aligned} & \text { Given, } z_r=\cos \left(\frac{\pi}{2^{\prime}}\right)+i \sin \left(\frac{\pi}{2^r}\right) \\ & \therefore z_1 z_2 z_3 \ldots=e^{i \frac{\pi}{2}} \cdot e^{i \frac{\pi}{2^2}} \cdot e^{i \frac{\pi}{2^3}} \ldots \\ & =e^{i\left(\frac{\pi}{2}+\frac{\pi}{2^2}+\frac{\pi}{2^3}+\ldots\right)} \\ & =e^{i\left(\frac{\pi / 2}{1}\right)}=e^{\lambda(\pi)} \\ & =\cos \pi+i \sin \pi=-1+i(0) \\ & =-1 \\ & \end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.