Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 10 9 Watt . The mass of the fuel consumed per hour , in the reactor, will be: (velocity of light, c is 3 × 10 8 m s - 1 )

Question

Imagine that a reactor converts all the given mass into energy and that it operates at a power level of 10 9 Watt . The mass of the fuel consumed per hour , in the reactor, will be: (velocity of light, c is 3 × 10 8 m s - 1 ), 6.6 × 10 - 5 g, 0.96 g, 4 × 10 - 2 g, 0.8 g

MARKS App · Accepted Answer

Power of reactor, P = E Δ t = Δ m c 2 Δ t (From mass-energy equivalence equation) Given in the problem power level = 10 9 Watt . ∆ m ∆ t = P c 2 = 10 9 3 × 10 8 2 ⇒ ∆ m ∆ t = 10 - 7 9 k g s - 1 The mass of fuel consumed per hour = 10 - 7 9 × 1000 g 3600 h - 1 = 4 × 10 - 2 g h - 1 .

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