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In 0.2 s, the current in a coil increases from 2.0 A to 3.0 A. If inductance of coil is 60 mH, then induced current in external resistance of $3 \Omega$ will be
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The correct answer is:
0.1 A
Induced emf
$\begin{aligned}|e| & =L \frac{d i}{d t}=\left(60 \times 10^{-3}\right) \times \frac{(3.0-2.0)}{0.2} \\ & =\frac{60 \times 10^{-3} \times 1}{0.2}=0.3 \mathrm{~V}\end{aligned}$
Induced current,
$\mathrm{t} i=\frac{e}{R}=\frac{0.3}{3}=0.1 \mathrm{~A}$
$\begin{aligned}|e| & =L \frac{d i}{d t}=\left(60 \times 10^{-3}\right) \times \frac{(3.0-2.0)}{0.2} \\ & =\frac{60 \times 10^{-3} \times 1}{0.2}=0.3 \mathrm{~V}\end{aligned}$
Induced current,
$\mathrm{t} i=\frac{e}{R}=\frac{0.3}{3}=0.1 \mathrm{~A}$
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