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Question: Answered & Verified by Expert
In 1 L saturated solution of AgClKspAgCl=1.6×10-10 , 0.1 mol of CuCl KspCuCl=1.0×10-6 is added. The resultant concentration of Ag+ in the solution is 1.6×10-x . The value of " x " is
ChemistryIonic EquilibriumJEE Main
Solution:
1063 Upvotes Verified Answer
The correct answer is: 7
Let the solubility of AgCl is x mol litre-1

AgClAg+x+Cl-x

And that of CuCl is y mol litre-1

CuClCu+y+Cl-y

Ksp of AgCl=Ag+Cl-1

1.6×10-10=xx+y ...(i)

Similarly Ksp of CuCl=Cu+Cl-

1.6×10-6=yx+y ...(ii)

On solving (i) and (ii)

Ag+=1.6×10-7

x=7

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