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Question: Answered & Verified by Expert
In ψ321, the sum of angular momentum, spherical nodes and angular node is
ChemistryStructure of AtomJEE Main
Options:
  • A 6h+4π2π
  • B 6h2π+3
  • C 6h+2π2π
  • D 6h+8π2π
Solution:
1544 Upvotes Verified Answer
The correct answer is: 6h+4π2π
ψ321:n=1,l=2,m=1

Angular momentum =h2πl(l+1)=6h2π

Spherical nodes =3-2-1=0; Angular node =2

Sum of all the above =6h2π+2=6h+4π2π

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