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In a $0.2 \mathrm{M}$ aqueous solution, lactic acid is $6.9 \%$ dissociated. The value of dissociation constant is
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Verified Answer
The correct answer is:
$95 \times 10^{-4}$
Given, $\alpha=6.9 \%$
$\therefore$ Degree of dissociation, $\alpha=\frac{6.9}{100}$
$\therefore \quad \alpha=0.069$
According to ostwald's dilution law,
$\begin{aligned}
& K_a=\alpha^2 C=(0.069)^2 \times 0.2 \\
& K_a=9.5 \times 10^{-4}
\end{aligned}$
$\therefore$ Degree of dissociation, $\alpha=\frac{6.9}{100}$
$\therefore \quad \alpha=0.069$
According to ostwald's dilution law,
$\begin{aligned}
& K_a=\alpha^2 C=(0.069)^2 \times 0.2 \\
& K_a=9.5 \times 10^{-4}
\end{aligned}$
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