In a 10 l i t r e box 2.5 m o l e hydroiodic acid is taken. After equilibrium 2 H I ⇌ H 2 + I 2 the concentration of H I is found to be 0.1 mol L − 1 . The concentration of H 2 at equilibrium in mol L - 1 , is

Question

In a 10 l i t r e box 2.5 m o l e hydroiodic acid is taken. After equilibrium 2 H I ⇌ H 2 + I 2 the concentration of H I is found to be 0.1 mol L − 1 . The concentration of H 2 at equilibrium in mol L - 1 , is, 2.4, 0.15, 1.5, 7.5 × 1 0 - 2

MARKS App · Accepted Answer

0.25 - 2 at equilibrium 0.25 - 2 x = 0.1 x = 7.5 × 1 0 - 2

Search any question & find its solution

Looking for more such questions to practice?