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Question: Answered & Verified by Expert
In ΔABC; with usual notations, bsinB-csinCsinB-C = ……
MathematicsProperties of TrianglesMHT CETMHT CET 2019 (Shift 2)
Options:
  • A b
  • B a+b+c
  • C a
  • D c
Solution:
1088 Upvotes Verified Answer
The correct answer is: a
We have, bsinB-csinCsinB-C
=ksinBsinB-ksinCsinCsinB-c (Using Sine rule)
=ksin2B-sin2CsinB-c
=ksinB+CsinB-CsinB-C
=ksinB+C
=ksin180o-A
=ksinA=a

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