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In $\triangle A B C$, if $\mathrm{A}=60^{\circ}$ and $\mathrm{B}=105^{\circ}$ then
$$
\begin{aligned}
& \frac{2 \mathrm{R}^2(b-c) \sin \mathrm{A} \sin \mathrm{B} \sin \mathrm{C}}{(b+c)(s-a \cos \mathrm{C}-c \cos \mathrm{A})(\mathrm{s}-a \cos \mathrm{B}-b \cos \mathrm{A})}= \\
\end{aligned}
$$
Options:
$$
\begin{aligned}
& \frac{2 \mathrm{R}^2(b-c) \sin \mathrm{A} \sin \mathrm{B} \sin \mathrm{C}}{(b+c)(s-a \cos \mathrm{C}-c \cos \mathrm{A})(\mathrm{s}-a \cos \mathrm{B}-b \cos \mathrm{A})}= \\
\end{aligned}
$$
Solution:
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Verified Answer
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