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In a binomial distribution, the occurrence and the nonoccurrence of an event are equally likely and the mean is 6 . The number of trials required is
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The correct answer is:
12
$\mathrm{P}=\mathrm{q}=\frac{1}{2}, \mathrm{nP}=6$
$\frac{\mathrm{n}}{2}=6 \Rightarrow \mathrm{n}=12$
$\frac{\mathrm{n}}{2}=6 \Rightarrow \mathrm{n}=12$
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