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In a box containing $\mathbf{1 0 0}$ bulbs, 10 are defective. The probability that out of a sample of 5 bulbs, none is defective is
(a) $10^{-1}$
(b) $\left(\frac{1}{2}\right)^5$
(c) $\left(\frac{9}{10}\right)^5$
(d) $\frac{9}{10}$
(a) $10^{-1}$
(b) $\left(\frac{1}{2}\right)^5$
(c) $\left(\frac{9}{10}\right)^5$
(d) $\frac{9}{10}$
Solution:
1815 Upvotes
Verified Answer
$p=\frac{1}{10}, q=\frac{9}{10}, \mathrm{n}=5, \mathrm{r}=0, \mathrm{P}(\mathrm{X}=0)=\left(\frac{9}{10}\right)^5$ Thus the option (c) is true.
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