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In a car a rear view mirror having a radius of curvature $1.50 \mathrm{~m}$ forms a virtual image of a bus located $10.0 \mathrm{~m}$ from the mirror. The factor by which the mirror magnifies the size of the bus is close to
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$0.07$
$\mathrm{u}=-10 \mathrm{~m}$
$\mathrm{R}=1.5 \mathrm{~m}$
$\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}=\frac{2}{\mathrm{R}}$
$\frac{1}{\mathrm{v}}-\frac{1}{10}=\frac{2}{1.5}$
$\mathrm{v}=\frac{30}{43}$
$\mathrm{~m}=-\frac{\mathrm{v}}{\mathrm{u}}=\frac{30}{43 \times 10} \simeq 0.07$
$\mathrm{R}=1.5 \mathrm{~m}$
$\frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}=\frac{2}{\mathrm{R}}$
$\frac{1}{\mathrm{v}}-\frac{1}{10}=\frac{2}{1.5}$
$\mathrm{v}=\frac{30}{43}$
$\mathrm{~m}=-\frac{\mathrm{v}}{\mathrm{u}}=\frac{30}{43 \times 10} \simeq 0.07$
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