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In a CE amplifier, $\beta=50, R_{L}=4 \mathrm{k} \Omega, R_{i}=500 \Omega$.
Power gain of the amplifier is
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Power gain of the amplifier is
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The correct answer is:
$2 \times 10^{4}$
Given, current gain, $\beta=50$
Input resistance, $R_{i}=500 \Omega$
Output resistance, $R_{L}=4 \mathrm{k} \Omega=4000 \Omega$
Voltage gain $=$ Current gain $\times \frac{R_{L}}{R_{i}}$
$=50 \times \frac{4000}{500}=400$
Power gain $=$ Current gain $\times$ Voltage gain
$=50 \times 400=2 \times 10^{4}$
Input resistance, $R_{i}=500 \Omega$
Output resistance, $R_{L}=4 \mathrm{k} \Omega=4000 \Omega$
Voltage gain $=$ Current gain $\times \frac{R_{L}}{R_{i}}$
$=50 \times \frac{4000}{500}=400$
Power gain $=$ Current gain $\times$ Voltage gain
$=50 \times 400=2 \times 10^{4}$
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