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In a $C E$ transistor amplifier, the signal voltage across the collector resistance is $2.5 \mathrm{~V}$. The input signal voltage is $0.02 \mathrm{~V}$. If the base and collector resistances are $1.5 \mathrm{k} \Omega$ and $2.5 \mathrm{k} \Omega$, then the current amplification factor is
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The correct answer is:
$75$
We know that
$A_v=\beta \frac{R_0}{R_i}, A_v=$ Voltage amplification factor
$\begin{aligned} & \Rightarrow \frac{2.5}{0.02}=\beta \times \frac{2.5}{1.5} \\ & \Rightarrow \beta=\frac{1.5}{0.02}=75\end{aligned}$
$A_v=\beta \frac{R_0}{R_i}, A_v=$ Voltage amplification factor
$\begin{aligned} & \Rightarrow \frac{2.5}{0.02}=\beta \times \frac{2.5}{1.5} \\ & \Rightarrow \beta=\frac{1.5}{0.02}=75\end{aligned}$
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