Search any question & find its solution
Question:
Answered & Verified by Expert
In a CE transistor when the base current increases by 60 $\mu \mathrm{A}$, change in base-emitter voltage is $1.2 \mathrm{~V}$. Then the input resistance is
Options:
Solution:
1441 Upvotes
Verified Answer
The correct answer is:
$20000 \Omega$
$\begin{aligned} & \text { } \mathrm{I}_{\mathrm{b}}=60 \mu \mathrm{A}=60 \times 10^{-6} \mathrm{~A} \\ & V_{\mathrm{BE}}=1.2 \mathrm{~V} \\ & \mathrm{~V}_{\mathrm{BE}}=\mathrm{I}_{\mathrm{b}} \mathrm{R}_{\text {in }} \\ & \Rightarrow \mathrm{R}_{\text {in }}=\frac{\mathrm{V}_{\mathrm{BE}}}{\mathrm{I}_{\mathrm{b}}}=\frac{1.2}{60 \times 10^{-6}}=20000 \Omega\end{aligned}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.