Search any question & find its solution
Question:
Answered & Verified by Expert
In a circle of diameter $40 \mathrm{~cm}$, the length of a chord is 20 $\mathrm{cm}$. Find the length of minor arc of the chord.
Solution:
1091 Upvotes
Verified Answer
Since radius $=$ length of chord $=20 \mathrm{~cm}$
$\Rightarrow \Delta \mathrm{OAB}$ is equilateral triangle
$\Rightarrow \quad \theta=60^{\circ} \Rightarrow \ell=r \theta$
$\Rightarrow \quad \ell=20 \times 60^{\circ} \times \frac{\pi}{180^{\circ}}=\frac{20 \pi}{3}$
$\therefore \quad \ell=\frac{20 \pi}{3} \mathrm{~cm}$
$\Rightarrow \Delta \mathrm{OAB}$ is equilateral triangle
$\Rightarrow \quad \theta=60^{\circ} \Rightarrow \ell=r \theta$
$\Rightarrow \quad \ell=20 \times 60^{\circ} \times \frac{\pi}{180^{\circ}}=\frac{20 \pi}{3}$
$\therefore \quad \ell=\frac{20 \pi}{3} \mathrm{~cm}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.