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In a class of \( 60 \) students, \( 25 \) students play cricket and \( 20 \) students play tennis, and \( 10 \) students
play both the games, then the number of students who play neither is
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play both the games, then the number of students who play neither is
Solution:
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Verified Answer
The correct answer is:
(25)
Given that $n=60, n(C)=25, n(T)=20$ and $n(C \cap T)=10$
Now,
$n(C \cup T)=n(C)+n(T)-n(C \cap T)$
$=25+20-10=35$
Therefore, $n(C \cap T)=n-n(C \cup T)$
$=60-35=25$
Now,
$n(C \cup T)=n(C)+n(T)-n(C \cap T)$
$=25+20-10=35$
Therefore, $n(C \cap T)=n-n(C \cup T)$
$=60-35=25$
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